f(x)=(2x+5)(x^2-2x-5)

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Solution for f(x)=(2x+5)(x^2-2x-5) equation: 


Simplifying
f(x) = (2x + 5)(x2 + -2x + -5)

Multiply f * x
fx = (2x + 5)(x2 + -2x + -5)

Reorder the terms:
fx = (5 + 2x)(x2 + -2x + -5)

Reorder the terms:
fx = (5 + 2x)(-5 + -2x + x2)

Multiply (5 + 2x) * (-5 + -2x + x2)
fx = (5(-5 + -2x + x2) + 2x * (-5 + -2x + x2))
fx = ((-5 * 5 + -2x * 5 + x2 * 5) + 2x * (-5 + -2x + x2))
fx = ((-25 + -10x + 5x2) + 2x * (-5 + -2x + x2))
fx = (-25 + -10x + 5x2 + (-5 * 2x + -2x * 2x + x2 * 2x))
fx = (-25 + -10x + 5x2 + (-10x + -4x2 + 2x3))

Reorder the terms:
fx = (-25 + -10x + -10x + 5x2 + -4x2 + 2x3)

Combine like terms: -10x + -10x = -20x
fx = (-25 + -20x + 5x2 + -4x2 + 2x3)

Combine like terms: 5x2 + -4x2 = 1x2
fx = (-25 + -20x + 1x2 + 2x3)

Solving
fx = -25 + -20x + 1x2 + 2x3

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'x'.
f = -25x-1 + -20 + x + 2x2

Simplifying
f = -25x-1 + -20 + x + 2x2

Reorder the terms:
f = -20 + -25x-1 + x + 2x2

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